(Q7) A wire of length 18 m had been tied with electric pole at an angle of elevation 30^o with the ground. As it is covering a long distance, it was cut and tied at an angle of elevation 60^o with the ground. How much length of the wire was cut ?

Solution :

Length of the wire = 18 m

Let the length of the wire removed = x

Height of the pole be = h

From the figure

√(-x) = ×

√ - √ x =

√ x = √ -

√ x = (√ - )

x = √3(√ - ) = - √3

x = - 10.392 = .608m